This article presents a worked example on the design of a pile cap using bending theory. The pile cap shall be proportioned, designed for bending, vertical shear, as well as verified for punching shear both at column perimeter and control perimeter all according to EN 1992-1-1-2004 (Eurocode 2).
The pile cap to be designed is to transmit column loads to piles. A geotechnical test has been carried out on the site located at Greenwich, South-East London. Due to the occurrence of London clay, which is highly unstable, on the upper 6m layer on the site, it is recommended that a deep foundation in the form of piles to a depth of 9m is adopted. The recommended pile size is 600mm with safe working load of 400KN. The characteristics strength of concrete and reinforcement for the pile cap are 25MPa and 500MPa respectively. The dimension of the column, and the load acting on it are given below.
Column: Size = 300 x 300mm
Dead Load = 1205KN
Live Load = 291KN
Estimate the number of piles required
Calculate the number of piles to support the column load.
Total service load on the column = 1205 + 291 = 1496KN
No of piles = Total service load/capacity of a pile = 1496/400 = 3.74
Adopt 4 number of piles
Determine the size and Dimension of the Pile cap
The distance between each pile shall be kØ
K =3,
Ø = 600mm
kØ = 3 x 600 = 1800
Edge distance = 150mm
Since the piles are four then they will be arranged in a square array so that they can be symmetrically distributed under the column.
The length of each side of pile cap = Pile dist + 2 x Ø/2 + 2 x edge distance
= 1800 + 2 x 300 + 2 x 150 = 2700mm
The height of this pile cap was taken as 1350mm when this pile cap was design using strut-and-tie method. However, the height of the pile cap shall be drastically reduced here so that the pile cap shall be designed using bending theory.
We shall assume the height of the pile cap to 900mm
The layout of the pile cap is shown below

Design the pile cap for flexure
Since the pile cap is to be designed using bending theory, we shall analyse the pile cap for maximum bending moment. This shall govern the main reinforcement in the pile cap.
Determine the moment in pile cap
The critical moment in the pile cap shall be taken from the centre of a pile to the face of the column.
N = Ultimate axial load = 1.35 x 1205 + 1.5 x 291 = 2063.25KN
Pile Reaction = 2063.25KN/4 = 515.81KN
L = distance from pile centre to column face = 1800/2 = 900mm
Max moment = Pile Reaction x L = 515.81 x 0.9 = 464.23KNm
Design for the computed Moment
- Calculate the effective depth
Assumptions
Cover = 50mm
Main reinforcement diameter = 20mm
Diameter of links = 10mm
Effective depth = h-c-ᴓ-ᴓ/2
= 900-50-10-20/2
= 830mm
2) Check whether section is to be designed as singly or doubly reinforced beam
$ K\,=\,\,\frac{M}{bd^2f_{ck}} $
$ K\,=\,\,\frac{464.23×10^6}{2700×830^2×25} $
= 0.01
Since K (0.01) < K’ (0.168); design as singly reinforced.
3) Calculate the lever arm (Z)
$ Z\,\,=\,\,d\left( 0.5+\sqrt{\text{0.25}-\,\,\frac{K}{1.134}} \right) $
$ Z\,\,=\,\,830\left( 0.5+\sqrt{\text{0.25}-\,\,\frac{0.01}{1.134}} \right) $ = 822.63
Since 822.63 > 0.95d (788.5): use Z = 788.5
4. Calculate the area of steel
$ A_{st\,\,=\,\,\frac{M_{Ed}}{0.87f_{yk}Z}} $
$ A_{st\,\,=\,\,\frac{464.23×10^6} {0.87x500x788.5}} $
Ast = 1353mm2
Check minimum area of reinforcement
Asmin = 0.26 x fctm/fyk x b x d ≥ 0.0013bd
Fctm = 0.3 x fck^(2/3) = 0.3 x 25^(2/3) = 2.57MPa
Asmin = 0.26 x 2.57/500 x 2700 x 830
Asmin = 2989mm²
Since the minimum area of reinforcement (2989mm²) is greater than area of steel required (1353mm²), then provide minimum area of steel.
Provide 12Y20 @ 225c/c (3770.4mm²) at the bottom along the two directions.
Top Face Reinforcement
Although EC2 allow for the top of a pile cap to be left unreinforced. It is however a good practice to provide them with minimum reinforcement against secondary stresses.
Since minimum reinforcement is already calculated for the bottom face, hence:
Provide 12Y20 @ 180c/c (2989mm²) at the top face along the two directions.
Check the Pile Cap for Vertical Shear
Vertical shear shall be provided at Ф/5 within the pile diameter (Click overview of pile cap design for more explanation on concept)
Shear at critical section = Reaction of two piles within the critical section
Shear at critical section = 2063/2 = 1031.5
Calculate av to allow for shear enhancement. av is the distance from the face of the column to one-fifth of the diameter of the pile.
av = 1800/2 – 600/2 – 300/2 + 600/5 = 570
Shear enhancement =av/2d
Effective shear = VED x av/2d = $ \frac{\text{1031.5}\times \,\,570}{\text{2}\times \,\,830} $ =257.875KN
Calculate the shear resistance without shear reinforcement
vRdc x bwd = (0.12K(100ρLfck)1/3)bwd ≥ vmin bwd
K = (1 +√200/d) ≤ 2.0
K = (1 +√200/830) = 1.49
ρL = Asl/bwd ≤ 0.02
ρL = (1353) / (2700 × 830) = 0.0013
vRdc = {0.12 x 1.49 (100 x 0.0013 x 25)1/3} ≥ vmin
vRdc = 0.597 N/mm²
Calculate the minimum resistance without reinforcement.
vmin = {0.035K³/2fck1/2}
vmin = 0.035 x 1.493/2 x 251/2 = 0.319 N/mm²
Since vRdc (0.597N/mm²) > vmin (0.319 N/mm²); hence vRdc passes minimum reinforcement requirement
Convert the shear capacity to resistance and compare against design shear force.
VRdc = vRdc x bd
VRdc = 0.597 x 2700 x 830 x 10^ (-3) = 1336.9KN
Since VED < VRdc the section is adequate for one way shear
Check the Pile Cap for Punching Shear
The punching shall be checked at the column perimeter and at perimeter 2d from the column face
Punching shear at column perimeter
Shear force acting on column = 2063KN
Calculate the maximum resistance of the compressive struct
vRDmax = 0.3 (1 -fck/250)fcd
fcd = fck/1.5 = 25/1.5 = 16.67 N/mm2
vRDmax = 0.3 (1 -25/250)16.67
vRDmax =4.5 N/mm²
Shear resistance (VRDmax) = vRDmax ud
where u is the perimeter of the column Shear resistance
(vRDmax) = 4.5 x 4(300) x x 10 ^ (-3)
VRDmax = 4482KN
VRDmax > VEd, the section passes punching check
Check Punching shear at basic control perimeter
Since the piles at spaced at not more than 3 x pile diameter, then punching shear check at basic control perimeter is not necessary.
Circumferential Reinforcement
The circumferential reinforcement should be provided in accordance with surface reinforcement for deep beams by providing 0.2% of reinforcement according to the UK national annex. This will however result to large area of reinforcement. We shall instead provide the circumferential reinforcement following the guidance of IStructE EC2 design manual. Hence, we shall Y12@150mm c/c